Scala隐式转换和隐式参数

implicit def a(d: Double) = d.toInt
//不加上边这句你试试
val i1: Int = 3.5
println(i1)

class RichFile(val from: File) {
  def read = Source.fromFile(from.getPath).mkString
}
 
implicit def file2RichFile(from: File) = new RichFile(from)
 
val contents = new File("C:\\Users\\61661\\Desktop\\scala笔记.txt").read
println(contents)

implicit val name = "Nick"
def person(implicit name: String) = name
println(person)

implicit val name = "Nick"
implicit val name2 = "Nick"
def person(implicit name: String) = name
println(person)

def foo(msg : String) = println(msg)
implicit def intToString(x : Int) = x.toString
foo(10)

class Dog {
  val name = "金毛"
}
 
class Skill{
  def fly(animal: Dog, skill: String) = println(animal.name   "已领悟"   skill)
}
 
object Learn{
  implicit def learningType(s : Dog) = new Skill
}
 
object Main2 extends App{
  override def main(args: Array[String]): Unit = {
    import unit15.Learn._
    val dog = new Dog
    dog.fly(dog, "飞行技能")
  }
}

object StringUtils {
  implicit class StringImprovement(val s : String){ //隐式类
    def increment = s.map(x => (x  1).toChar)
  }
}
object Main3 extends  App{
  import unit15.StringUtils._
  println("mobin".increment)
}